12x^2+1/3x^2+10(2x+1/3x)+11=0

Solution for 12x^2+1/3x^2+10(2x+1/3x)+11=0 equation:

x in (-oo:+oo)

10*(2*x+(1/3)*x)+12*x^2+(1/3)*x^2+11 = 0

12*x^2+(x^2)/3+7/3*10*x+11 = 0

(3*12*x^2)/3+(x^2)/3+(7/3*3*10*x)/3+(3*11)/3 = 0

3*12*x^2+x^2+7/3*3*10*x+3*11 = 0

36*x^2+x^2+70*x+33 = 0

37*x^2+70*x+33 = 0

37*x^2+70*x+33 = 0

37*x^2+70*x+33 = 0

DELTA = 70^2-(4*33*37)

DELTA = 16

DELTA > 0

x = (16^(1/2)-70)/(2*37) or x = (-16^(1/2)-70)/(2*37)

x = -33/37 or x = -1

(x+1)*(x+33/37) = 0

((x+1)*(x+33/37))/3 = 0

((x+1)*(x+33/37))/3 = 0 // * 3

(x+1)*(x+33/37) = 0

( x+1 )

x+1 = 0 // - 1

x = -1

( x+33/37 )

x+33/37 = 0 // - 33/37

x = -33/37

x in { -1, -33/37 }